Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousHard2 minPYQ_2019
PhysicsHardsingle choice

The displacement of a particle executing simple harmonic motion is given by,
y=A0+Asinωt+Bcosωt.
Then, the amplitude of its oscillation is given byNEET 2019 (All India)

Options:

Answer:
B
Solution:

y=A0+Asinωt+Bcosωt
=A0+A2+B2·AA2+B2sinωt+BA2+B2cosωt
=A0+A2+B2sinωt+φ
Amplitude=A2+B2

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2019

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