Physics - SHM Question with Solution | TestHub

Time period of both$A$and$B$.

$2\pi \sqrt{\frac{l}{g}}$

$A$and$B$collide after time$\frac{T}{4}$

After first collision,$B$acquires amplitude of$A$and second collision takes place after additional time of$\frac{T}{4}+\frac{T}{4}=\frac{T}{2}$after second collision$B$acquires its own amplitude and reaches its initial position after additional time of$\frac{T}{4}$

In this process time taken is$=\frac{T}{4}+\frac{T}{4}+\frac{T}{4}+\frac{T}{4}$

$\Rightarrow T=2\pi \sqrt{\frac{l}{g}}$