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PhysicsSHMMiscellaneousEasy2 minPYQ_2009

PhysicsEasysingle choice

If a simple pendulum oscillates with an amplitude of $50 mm$ and time period of $2 s$ , then its maximum velocity is

Answer:

Solution:

$v_{m a x} = aω = a \times \frac{2 π}{T} = (50 \times 1 0^{- 3}) \times \frac{2 π}{2}$ $= 0.15 ms^{- 1}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2009

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