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Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyEasy2 minPYQ_2020

PhysicsEasysingle choice

The potential energy of a particle executing S.H.M is $2.5 J$ , when its displacement is half of its amplitude. The total energy of the particle is

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Answer:

Solution:

$P . E . = \frac{1}{2} m ω^{2} x^{2} = 2.5 J$

As $x = \frac{A}{2}$

$\frac{1}{2} m ω^{2} {(\frac{A}{2})}^{2} = 2.5$

$∴ \frac{1}{2} m ω^{2} \frac{A^{2}}{4} = 2.5$

$∴ \frac{1}{2} m ω^{2} A^{2} = 10 J$

Total energy of system $= \frac{1}{2} m ω^{2} A^{2} = 10 J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2020

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