Physics - SHM Question with Solution | TestHub

Time period to cross the earth once along its diameter$=\frac{T}{2}$

$=\frac{1}{2}\left(2\pi \sqrt{\frac{R}{g}}\right)$

$=\pi \sqrt{\frac{R}{g}}$

Where,$R$is the radius of the earth

$=3.14\times \sqrt{\frac{6.4\times {10}^6}{9.8}}=2537.5\mathrm{ s}$

$=42.3\mathrm{m}\mathrm{i}\mathrm{n}$