There is a pendulum executing simple harmonic motion and its maximum kinetic energy is $K_{1} .$ If the length of the pendulum is doubled and it performs simple harmonic motion with the same angular amplitude as in the first case, its maximum kinetic energy is $K_{2}$ . Relation between them is

Question

TestHub · Accepted Answer

Maximum kinetic energy = 1 2 m ω 2 A 2 ω = g L A = L θ KE = 1 2 m g L × L 2 θ 2 , KE = 1 2 mgL θ 2 K 1 = 1 2 mgL θ 2 If Length Is Double K 2 = 1 2 mg ( 2 L ) θ 2 [Here we are assuming angular amplitude is same] K 1 K 2 = 1 2 m g l θ 2 1 2 m g ( 2 L ) θ 2 = 1 2 K 2 = 2 K 1

Physics - SHM Question with Solution | TestHub

Options:

Doubts & Discussion