The length of the seconds pendulum is decreased by 0.3 cm when it is shifted from place A to place B. If the acceleration due to gravity at place A is 981 cm / s 2 , the acceleration due to gravity at

Question

The length of the seconds pendulum is decreased by 0.3 cm when it is shifted from place A to place B. If the acceleration due to gravity at place A is 981 cm / s 2 , the acceleration due to gravity at place B is ( Take π 2 = 10 )

TestHub · Accepted Answer

For seconds pendulum T = 26 T = 2 π g 1 ​ ​ ∴ 2 = 2 π g ℓ ​ ​ of 1 = π g l ​ ​ gquaring: 1 = π 2 g ℓ ​ t = π 2 9 ​ = 10 981 ​ = 98.1 cm At place B, ℓ ′ = 98.1 − 0.3 = 97.8 cm Again, 2 = 2 π g ′ ℓ ′ ​ ​ 1 = π 2 g ′ L ​ ∴ g ′ = π 2 ℓ ′ = 10 × 97.8 = 978 cm / s 2

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