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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020
PhysicsEasysingle choice

A particle of massmis moving along thex-axisunder the potential V(x)= k x 2 2 + λ x ′ wherekand x ′ are positive constants of appropriate dimensions. The particle is slightly displaced from its equilibrium position. The particle oscillates with the angular frequencyωgiven by

Options:

Answer:
C
Solution:

Given, V(x)= k x 2 2 + λ x ′

F=-∂V(x)∂x= -kx

a=-kmx

ω2=km

ω=km

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period
⏱ 2mℹ️ Source: PYQ_2020

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