Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyEasy2 minPYQ_2020

PhysicsEasysingle choice

A body performs linear simple harmonic motion of amplitude 'A". At what displacement from the mean position, the potential energy of the body is one fourth of its total energy?

Options:

Answer:

Solution:

Total energy $= \frac{1}{2} KA^{2}$ Potential energy $= \frac{1}{2} kx^{2}$ If P.E. $= \frac{1}{4} (K . E .)$ then $\frac{1}{2} kx^{2} = \frac{1}{4} (\frac{1}{2} kA^{2})$ $∴ x^{2} = \frac{A ^{2}}{4}$ or $x = \frac{A}{2}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...