Physics - SHM Question with Solution | TestHub

$x=A\sin \omega t$

(A) x = 0 to A/2:$\sin \omega t=\frac{1}{2}\Rightarrow \omega t=\frac{\pi }{6}\Rightarrow t=\frac{T}{12}$Correct.

(B) A/2 to A: ωt goes from π/6 to π/2:$t=\frac{T}{6}$Correct.

(C) 0 to A:$t=\frac{T}{4}$Correct.

(D) 0 to A/√2:$\omega t=\frac{\pi }{4}\Rightarrow t=\frac{T}{8}$Correct.

Hence all four options.