A simple harmonic motion is represented by: y = 5 sin 3 π t + 3 cos 3 π t cm The amplitude and time period of the motion are:

y = 5 sin 3 π t + 5 3 cos 3 π t A 2 = 5 2 + 5 3 2 = 10 2 A = 10 cm ω = 3 π T = 2 π ω = 2 3 s

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PhysicsSHMCalculation of time periodEasy2 minPYQ_2019

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A simple harmonic motion is represented by:
$y = 5 (\sin 3 π t + \sqrt{3} \cos 3 π t) cm$
The amplitude and time period of the motion are:

Question diagram: A simple harmonic motion is represented by: y = 5 sin 3 π t

Options:

Answer:

Solution:

$y = 5 \sin (3 π t) + 5 \sqrt{3} \cos (3 π t)$

$A^{2} = 5^{2} + {(5 \sqrt{3})}^{2} = 10^{2}$

$A = 10 cm$

$ω = 3 π$

$T = \frac{2 π}{ω} = \frac{2}{3} s$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2019

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