Physics - SHM Question with Solution | TestHub
A block is placed on a horizontal plank. The plank is performing SHM along a vertical line with amplitude of 40 cm. The block just loses contact with the plank when the plank in momentarily at rest.
List - I | List - II |
|---|---|
(P) The period of oscillation in sec is | (1) Halfway down the mean position |
(Q) The block weights 1.5 times its weight on the plank | (2) |
(R) The block weights on the plank double its weight | (3) Velocity of the plank is maximum |
(S) The block weights its true weight on the plank | (4) The plank is at one of the positions of momentary rest |
Options:
Answer:
Solution:
(P).
N = m(g + a). At the mean position a = 0, so N = mg: true weight (S).
Maximum upward acceleration is at the lowest point; N = 2mg needs a = g, reached at the extreme - position of momentary rest (R).
N = 1.5mg needs a = g/2, halfway down the mean position (Q). Option (A).
