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PhysicsSHMCalculation of time periodEasy2 minPYQ_2019
PhysicsEasysingle choice

A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder areThandTcrespectively, then:

Options:

Answer:
B
Solution:

Time period of any magnetic body place in an external magnetic field is:-

T=2πIMB

Thoop=2πmR2MB......(1)Ihoop=mR2

Tc=2πmR22M2B ......(2)ISolid cylinder=mR22

From(1)and(2)

Th=Tc

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
2mℹ️ Source: PYQ_2019

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