Physics - SHM Question with Solution | TestHub

Here, $\mathrm{m}=1\mathrm{kg}$ The given equation of SHM is $x=6.0\cos \left(100t+\frac{\pi }{4}\right)$ Comparing it with equation of SHM, $\begin{array}{rl}x& =A\cos (\omega t+\varphi ),\text{ we have }\\ A& =6.0\mathrm{cm}=\frac{6}{100}\mathrm{m}\end{array}$ and $\omega =100\mathrm{rad}/\mathrm{s}$ Maximum kinetic energy $=\frac{1}{2}\mathrm{m}{\left({\mathrm{v}}_{\max }\right)}^2$ $=\frac{1}{2}\mathrm{m}(\mathrm{A}\omega {)}^2=\frac{1}{2}\times 1\times {\left[\frac{6}{100}\times 100\right]}^2=18\mathrm{J}$