Physics - SHM Question with Solution | TestHub

Maximum tension in the string is $\begin{array}{rl}& T_{\max }=mg+\frac{m{v}^2}{l}\\ & =mg+\frac{2mgl}{l}\left(1-\cos {\theta }_0\right)\\ & =mg+2mg\left(1-1+\frac{{\theta }_0^2}{2}\right)\left(\text{ since }{\theta }_0\text{ is small }\right)\\ & =mg\left(1+{\theta }_0^2\right)\end{array}$