Physics - SHM Question with Solution | TestHub

$$\begin{array}{rl}& \mathrm{x}=\mathrm{a}\sin \omega \mathrm{t}\Rightarrow \frac{\mathrm{x}}{\mathrm{a}}=\sin \omega \mathrm{t}\\ & \mathrm{x}=\mathrm{a}\cos \omega \mathrm{t}\Rightarrow \frac{\mathrm{x}}{{\mathrm{a}}^2}=\cos \omega \mathrm{t}\\ & \therefore \frac{{\mathrm{x}}^2}{{\mathrm{a}}^2}+\frac{{\mathrm{y}}^2}{{\mathrm{b}}^2}=1\\ & \text{ or }{\mathrm{x}}^2+{\mathrm{y}}^2={\mathrm{a}}^2\end{array}$$ This is equation of circle, so the particle follows a circular path.