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PhysicsSHMCalculation of time periodMedium2 minPYQ_2006

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The maximum velocity of a particle, executing simple harmonic motion with an amplitude $7 mm$ , is $4.4 m / s$ . The period of oscillation is

Answer:

Solution:

$A ω = V_{m a x}$ $T = \frac{2 π}{ω} = \frac{2 π A}{v _{m a x}} = 0.01 sec$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2006

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