Comprehension: A block weighing 10 N is attached to the lower end of a vertical spring ( k = 200 N/m), the other end attached to a ceiling. The block oscillates vertically and has kinetic energy 2.0 J

Question

Comprehension: A block weighing 10 N is attached to the lower end of a vertical spring ( $k = 200$ N/m), the other end attached to a ceiling. The block oscillates vertically and has kinetic energy 2.0 J as it passes through the point where the spring is unstretched. The amplitude of the oscillation of the block is:

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Answer:

C

Solution:

$\frac{1}{2} k A^{2} = K E_{ma x} = 2.25$ J, so $A^{2} = \frac{2 ( 2.25 )}{200} = 0.0225$ and $A = 0.15$ m = $15$ cm.

TestHub · Accepted Answer

2 1 ​ k A 2 = K E ma x ​ = 2.25 J, so A 2 = 200 2 ( 2.25 ) ​ = 0.0225 and A = 0.15 m = 15 cm.

Physics - SHM Question with Solution | TestHub

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