A mass is suspended separately by two different springs in successive order, then the time period is $T_{1}$ and $T_{2}$ , respectively. If it is connected by both spring as shown in figure, then the time period $T_{0}$ , so the correct reaction is:
NEET 2002

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Time period of spring T = 2 π K m ​ ​ ​ ∴ K = 4 π 2 T 2 m ​ ⇒ K ∝ T 2 1 ​ ​ For parallel combination of spring K = K 1 ​ + K 2 ​ ​ ∴ T 0 2 ​ 1 ​ = T 1 2 ​ 1 ​ + T 2 2 ​ 1 ​ ⇒ T 0 − 2 ​ = T 1 − 2 ​ + T 2 − 2 ​ ​

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