A potential barrier of 0.50 V exists across a p-n junction. If the depletion region is 5.0 × 1 0 − 7 m wide, the average intensity of the electric field is

E = d V = 5.0 × 1 0 − 7 0.50 E = 1.0 × 1 0 6 V m − 1

Start Free Mock LoginAlready registered? Login here

Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionMedium2 minQB

PhysicsMediumsingle choice

A potential barrier of $0.50 V$ exists across a p-n junction. If the depletion region is $5.0 \times 1 0^{- 7} m$ wide, the average intensity of the electric field is

Options:

Answer:

Solution:

$E = \frac{V}{d} = \frac{0.50}{5.0 \times 1 0 ^{- 7}}$

$E = 1.0 \times 1 0^{6} V m^{- 1}$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...