In the given circuit, the value of current $I_{L}$ will be _____ $mA .$ (When $R_{L} = 1 kΩ$ )

Question

In the given circuit, the value of current I L will be _____ mA . (When R L = 1 kΩ )

TestHub · Accepted Answer

Potential drop across the branch containing load resistance will be $5 V$ due to Zener diode. Therefore, potential drop across $800 Ω$ will be, $10 V - 5 V = 5 V$ .

Now, current through battery will be,

$I = \frac{5}{800} \times 1000$ $= 6.25 mA$

Current through load will be,

$I_{L} = \frac{5}{1000} A$

$= 5 mA$

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