The forward biased diode connection is

Question

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A p-n junction diode is forward biased when its p-side (anode) is at a higher potential than its n-side (cathode), i.e., $V_{p} > V_{n}$ .

Let us check the potential difference for each given option:

For the first circuit:
$V_{p} = + 2 V$ and $V_{n} = - 2 V$
Since $V_{p} > V_{n}$ , the diode is forward biased.

For the second circuit:
$V_{p} = + 2 V$ and $V_{n} = + 4 V$
Since $V_{p} < V_{n}$ , the diode is reverse biased.

For the third circuit:
$V_{p} = - 3 V$ and $V_{n} = - 3 V$
Since $V_{p} = V_{n}$ , the diode is unbiased.

For the fourth circuit:
$V_{p} = - 2 V$ and $V_{n} = + 2 V$
Since $V_{p} < V_{n}$ , the diode is reverse biased.

Therefore, only the first circuit represents a forward biased diode.

Answer:

Physics - Semiconductors Question with Solution | TestHub

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