In the study of transistor as an amplifier, the ratio of collector current to emitter current is 0.98 then the ratio of collector current to base current will be

Question

TestHub · Accepted Answer

The ratio of collector current to emitter current at constant collector base voltage is the current the amplification factor and given by
$α = \frac{l_{C}}{l_{E}} = 0.98$ (Given)
The ratio of collector current to the base current at constant collector-emitter voltage is given by
$β = \frac{l_{C}}{l_{B}}$
These are related as $β = \frac{α}{1 - α}$
$\Rightarrow β = \frac{0.98}{1 - 0.98} = \frac{0.98}{0.02} = 49$

Physics - Semiconductors Question with Solution | TestHub

Options:

Doubts & Discussion