Physics - Semiconductors Question with Solution | TestHub

From the given logic circuit, the boolean expressions for the outputs of the two AND gates are:
$C=A\cdot B$
$D=\bar{A}\cdot B$

The final output $E$ from the OR gate is:
$E=C+D$
$E=A\cdot B+\bar{A}\cdot B$

Taking $B$ common, we get:
$E=B(A+\bar{A})$
Since $A+\bar{A}=1$,
$E=B\cdot 1$
$E=B$

Therefore, the output $E$ is identical to the input $B$.
The corresponding truth table is:
$A=0,B=0\Rightarrow E=0$
$A=0,B=1\Rightarrow E=1$
$A=1,B=0\Rightarrow E=0$
$A=1,B=1\Rightarrow E=1$

Answer: