If two inputs of a NOR gate are shorted, the resulting gate is

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The Boolean expression for a NOR gate with inputs $A$ and $B$ is $Y = \overline{A + B}$ .

When the two inputs are shorted, $A = B$ .

Substituting $B = A$ in the expression, we get $Y = \overline{A + A}$ .

According to Boolean algebra, $A + A = A$ .

Therefore, $Y = \overline{A}$ , which is the Boolean expression for a NOT gate.

Answer: a NOT gate.

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