Physics - Semiconductors Question with Solution | TestHub

Given maximum power rating $P_{max}=1.0$ W and Zener voltage $V_Z=4.0$ V.

The maximum current $I_{max}$ flowing through the Zener diode is given by the relation:

$P_{max}=V_Z\times I_{max}$

$I_{max}=\frac{P_{max}}{V_Z}$

$I_{max}=\frac{1.0}{4.0}=0.25$ A

$I_{max}=0.25\times 1000$ mA $=250$ mA

Answer: $250$ mA