Physics - Semiconductors Question with Solution | TestHub

The given circuit consists of a NOR gate followed by a NOT gate.

The output of the NOR gate is given by:
$C=\overline{A+B}$

This output $C$ is then passed through a NOT gate. The final output $Y$ is:
$Y=\overline{C}$

Substituting the value of $C$, we get:
$Y=\overline{\overline{A+B}}$

Using the property of Boolean algebra $\overline{\overline{X}}=X$, we have:
$Y=A+B$

This is the Boolean expression for an OR gate.

Answer: $\text{OR},\text{A}+\text{B}$