In an n-p-n transistor amplifier, the collector current is 8 mA . If 80% of the electrons from the emitter reach the collector, then ( α and β are current ratios)

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Given I C ​ = 8 mA and I C ​ = 80% of I E ​ = 0.8 I E ​ . I E ​ = 0.8 I C ​ ​ = 0.8 8 ​ = 10 mA I B ​ = I E ​ − I C ​ = 10 − 8 = 2 mA α = I E ​ I C ​ ​ = 10 8 ​ = 0.8 β = I B ​ I C ​ ​ = 2 8 ​ = 4.0 Answer: α = 0.8 , β = 4.0

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