Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPhysics of semiconductorMedium2 minPYQ_2024

PhysicsMediumsingle choice

The acceptor level of a p-type semiconductor is $6 eV$ . The maximum wavelength of light which can create a hole would be : Given $hc = 1242 eV nm$ .

Answer:

Solution:

$Energy = \frac{hc}{λ} E = \frac{1240}{λ ( nm )} eV 6 = \frac{1240}{λ ( nm )} λ = \frac{1240}{6} = 207 nm$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:Physics of semiconductor

⏱ 2mℹ️ Source: PYQ_2024

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