Physics - Semiconductors Question with Solution | TestHub

From the given logic circuit diagram, we can identify the following gates:
1. The gate connected to input $A$ is a NOT gate. Its output is $\bar{A}$.
2. The gate connected to inputs $B$ and $C$ is a NAND gate. Its output is $\overline{B\cdot C}$.
3. These two outputs are fed into an OR gate. Therefore, the Boolean expression for the final output $Y$ is:
$Y=\bar{A}+\overline{B\cdot C}$

Case 1: When all three inputs are low ($A=0,B=0,C=0$)
$Y=\bar{0}+\overline{0\cdot 0}$
$Y=1+\bar{0}$
$Y=1+1=1$

Case 2: When all three inputs are high ($A=1,B=1,C=1$)
$Y=\bar{1}+\overline{1\cdot 1}$
$Y=0+\bar{1}$
$Y=0+0=0$

The output $Y$ when the inputs are first low and then high is $1$ and $0$ respectively. Thus, the correct pair is $(1,0)$.

Answer: $(1,0)$