Physics - Semiconductors Question with Solution | TestHub

${\mathrm{V}}_1=\frac{400}{100+400}\times 12\mathrm{V}=\frac{4}{5}\times 12=\frac{48}{5}\mathrm{V}$
here, ${\mathrm{V}}_1>{\mathrm{V}}_{\mathrm{z}},({\mathrm{V}}_{\mathrm{z}}=$ Zener Voltage $)$ So, Zener breakdown will be take place So, voltage across $400\Omega$ will be 4 V
$\mathrm{I}=\frac{4}{400}\mathrm{A}=\frac{1}{100\mathrm{A}}=10\mathrm{mA}$