Physics - Semiconductors Question with Solution | TestHub

Emitter current $I_E$ is proportional to the total number of electrons entering the emitter.

Since $2\%$ of electrons recombine in the base, the base current $I_B=0.02I_E$.

The remaining $98\%$ of electrons reach the collector, so the collector current $I_C=0.98I_E$.

The current ratio $\alpha$ is given by $\alpha =\frac{I_C}{I_E}=0.98$.

The current ratio $\beta$ is given by $\beta =\frac{I_C}{I_B}=\frac{0.98I_E}{0.02I_E}=49$.

Thus, $\alpha =0.98$ and $\beta =49$.

Answer: $0\cdot 98,49$