Physics - Semiconductors Question with Solution | TestHub

Let the inputs be $A$ and $B$. We need to find the logic gates that give an output $Y=1$ for the input combinations $(A=1,B=0)$ and $(A=0,B=1)$.

For an OR gate, the Boolean expression is $Y=A+B$.
If $A=1,B=0$, $Y=1+0=1$.
If $A=0,B=1$, $Y=0+1=1$.

For a NAND gate, the Boolean expression is $Y=\overline{A\cdot B}$.
If $A=1,B=0$, $Y=\overline{1\cdot 0}=\overline{0}=1$.
If $A=0,B=1$, $Y=\overline{0\cdot 1}=\overline{0}=1$.

For an AND gate, $Y=A\cdot B$.
If $A=1,B=0$, $Y=1\cdot 0=0$.

For a NOR gate, $Y=\overline{A+B}$.
If $A=1,B=0$, $Y=\overline{1+0}=\overline{1}=0$.

Thus, the two different logic gates that give an output of $1$ for both sets of inputs are NAND and OR.

Answer: 'NAND', 'OR'