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Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsTransistorMedium2 minPYQ_2020

PhysicsMediumsingle choice

In common emitter amplifier, input resistance is $1000Ω$ , peak value of input signal voltage is $5 mV$ and $β = 60$ . The peak value of output current is

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Solution:

$r_{L} = 1000Ω$ $v_{i} = 5 mV = 5 \times 1 0^{- 3} V$ $β = 60$ $I_{input} = \frac{5 \times 1 0 ^{- 3}}{1000} = 5 \times 1 0^{- 6} A$ $∴ I_{output} = 60 \times 5 \times 1 0^{- 6} A = 300 \times 1 0^{- 6} A$ $= 3 \times 1 0^{- 4} A$

Stream:MHT_CETSubject:PhysicsTopic:SemiconductorsSubtopic:Transistor

⏱ 2mℹ️ Source: PYQ_2020

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