Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionEasy2 minPYQ_2020

PhysicsEasysingle choice

For the circuit shown in the figure, determine the current through the Zener diode (Given: Zener diode is at break down voltage $V_{z} = 5.6 V$ )

Options:

Answer:

Solution:

$i_{1} - i_{2} = \frac{V_{z}}{800} = \frac{5.6}{800} = 7 mA$

For loop $ABCF$ ,

$9 - 200 i_{1} - V_{z} = 0$

$i_{1} = 0.017$ or $17 mA$

$i_{2} = (i_{1} - 7) mA$

$= 10 mA$

Subject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2020

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