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Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionEasy2 minPYQ_2016

PhysicsEasysingle choice

A zener diode is specified as having a breakdown voltage of $9.1 V$ , with a maximum power dissipation of $364 mW$ . What is the maximum current the diode can handle?

Options:

Answer:

Solution:

The maximum permissible current is $I_{Z_{m a x}} = \frac{P}{V _{Z}} = \frac{364 \times 1 0 ^{- 3}}{9.1} = 40 mA$

Stream:AIIMSSubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2016

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