Physics - Semiconductors Question with Solution | TestHub

The potential difference across the Zener diode and the resistance $R_2$ is the same because they are in parallel connection.

$V_{\mathrm{z}}=V_2=6 \mathrm{V}$

Let the potential difference across $R_1$ is $V_1$, then

$16=V_1+6$

$V_1=10 \mathrm{V}$

$I_1{R}_1=10$
$I_1=\frac{10}{1000}=0.01 \mathrm{A}$

$I_2{R}_2=6 \mathrm{V}$
$I_2=\frac{6}{1000}=0.006 \mathrm{A}$

$I=0.01-0.006=0.004 \mathrm{A}=4 \mathrm{mA}$