In the following logic circuit the sequence of the inputs $A, B$ are $(0, 0), (0, 1), (1, 0)$ and $(1, 1) .$ The output $Y$ for this sequence will be :

Question

In the following logic circuit the sequence of the inputs A , B are ( 0 , 0 ) , ( 0 , 1 ) , ( 1 , 0 ) and ( 1 , 1 ) . The output Y for this sequence will be :

TestHub · Accepted Answer

Look at the above circuit, the value of

P

can be found by the idea of AND gate,

P = A \cdot B

and the value of

Q

, can be calculated by the idea of OR gate,

Q = A + B

. Then expression for

Y

can be taken by the idea of NAND gate,

\Rightarrow Y = \bar{P \cdot Q}

by the idea of Demorgan's theorem,

Y = \bar{P} + \bar{Q} = \bar{A} + \bar{B} + \bar{A} \cdot \bar{B}

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