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Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The forbidden energy gap in Ge is 0.72 eV, given, $h c$ = 12400 eV- $Å$ . The maximum wavelength of radiation that will generate electron hole pair is

Options:

Answer:

Solution:

The forbidden Energy gap, $E_{g} = \frac{h c}{λ}$

λ = maximum wave length of radiation

$λ = \frac{h c}{E_{g}} = \frac{12400}{0.72} = 17222 Å$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SemiconductorsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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