A common emitter transistor amplifier has a current gain of 50 . If the load resistance is 4 kΩ and input resistance is 500 Ω .then the voltage gain of the amplifier is

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⇒ β = 50 ⇒ R L = 4 kΩ , R i = 500 Ω ⇒ V c e = I c R L , V b e = I b R i ⇒ β = I c I b = 50 ⇒ β = I c I b = 50 ⇒ A V = V c e V b e = I e I b × R L R i = 50 × 4 × 1000 500 = 400

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