Physics - Semiconductors Question with Solution | TestHub

Here, the output of these gate

$Y=\overline{\overline{A}.\overline{B}}$

But according to Boolean algebra,

$\overline{A}.\overline{B}=\overline{A+B}$

$\therefore Y=\overline{\overline{A}+\overline{B}}=A+B$

or$Y=A+B$

It means the whole circuit of gates behaves as$OR$gate