Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPhysics of semiconductorEasy2 minPYQ_2020

PhysicsEasysingle choice

A particular semiconductor in equilibrium has $1 \times 10^{16} {cm}^{- 3}$ donor atoms, $1.1 \times 10^{17} {cm}^{- 3}$ acceptor atoms. If the intrinsic carrier density $(n_{i})$ of the semiconductor is $10^{12} {cm}^{- 3}$ , then the electron density in it will be

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Answer:

Solution:

From mass action law,

$n_{e} n_{h} = n_{i}^{2}$

and $n_{h} = (1.1 \times 10^{17} - 10^{16}) {cm}^{- 3} = 10^{17} {cm}^{- 3}$

$∴ n_{e} = \frac{{(10^{12})}^{2}}{10^{17}} = 10^{7} {cm}^{- 3}$

Subject:PhysicsTopic:SemiconductorsSubtopic:Physics of semiconductor

⏱ 2mℹ️ Source: PYQ_2020

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