Physics - Semiconductors Question with Solution | TestHub

For zener break down potential difference across $800\Omega$ resistor will be $5.6\mathrm{V}$

${\mathrm{V}}_{\mathrm{z}}=5.6\mathrm{V}$

${\mathrm{i}}_2=\frac{{\mathrm{V}}_2}{800}=\frac{5.6}{800}=7\mathrm{mA}$
$\mathrm{\Delta V}$ across $200\Omega =9-5.6=3.4\mathrm{V}$
$i_1=\frac{3.4}{200}=17\mathrm{mA}$
${\mathrm{i}}_1={\mathrm{i}}_2+{\mathrm{i}}_{\mathrm{z}}$

${\mathrm{i}}_z=17\mathrm{mA}-7\mathrm{mA}=10\mathrm{mA}$