A silicon specimen is made into a p -type semiconductor by doping, on an average, one indium atom per 5 × 10 7 silicon atoms. If the number density of atoms in the silicon specimen is 5 × 10 28 atoms

Question

A silicon specimen is made into a p -type semiconductor by doping, on an average, one indium atom per 5 × 10 7 silicon atoms. If the number density of atoms in the silicon specimen is 5 × 10 28 atoms m - 3 , then the number of acceptor atoms in silicon per cubic centimetre will be

TestHub · Accepted Answer

Number density of atoms in silicon specimen

= ${5 \times 10}^{28}$ atoms- $m^{- 3} = {5 \times 10}^{22}$ atoms ${c m}^{- 3}$ .

Since, 1 atom of indium is doped in ${5 \times 10}^{7}$ silicon atoms, so total number of indium atoms doped per ${c m}^{3}$ of silicon will be

$n = \frac{{5 \times 10}^{22}}{{5 \times 10}^{7}} = 10^{15}$ atom- ${c m}^{- 3}$ .

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