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Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionMedium2 minPYQ_2019

PhysicsMediumsingle choice

The reverse break down voltage of a Zener diode is $5.6 V$ in the given circuit.

The current $I_{z}$ through the Zener is:

Options:

Answer:

Solution:

$i_{1} - i_{z} = \frac{V_{z}}{800} = \frac{5.6}{800} = 7 m A$
For loop ABCF,
$9 - 200 i_{1} - V_{z} = 0$
$i_{1} = 0.017 o r 17 m A$
$i_{z} = (i_{1} - 7) m A = 10 m A$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2019

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