Physics - Semiconductors Question with Solution | TestHub

${\text{V}}_{\text{i}}={\text{I}}_{\text{B}}{\text{R}}_{\text{B}}+{\text{V}}_{\text{B}\text{E}}$(By Kirchoff's Voltage Law)

$20={\text{I}}_{\text{B}}\times \left(500\times {10}^3\right)+0$

${\text{I}}_{\text{B}}=\frac{20}{500\times {10}^3}=40\mathrm{ \mu A}$

${\text{V}}_{\text{C}\text{C}}={\text{I}}_{\text{C}}{\text{R}}_{\text{C}}+{\text{V}}_{\text{C}\mathrm{E }}$(By Kirchoff's Voltage Law)

$20={\text{I}}_{\text{C}}\times \left(4\times {10}^3\right)+0$

${\text{I}}_{\text{C}}=5\times {10}^{-3}=5 \mathrm{mA}$

$\beta =\frac{{\text{I}}_{\text{C}}}{{\text{I}}_{\text{B}}}=\frac{5\times {10}^{-3}}{40\times {10}^{-6}}=125$