Physics - Semiconductors Question with Solution | TestHub

Here, $R=4\mathrm{k}\Omega =4\times 10^3\Omega$ $$V_i=60\mathrm{V}$$ Zener voltage $V_z=10\mathrm{V}$ $R_L=2\mathrm{k}\Omega =2\times 10^3\Omega$ Load current, $I_{\mathrm{L}}=\frac{V_Z}{R_L}=\frac{10}{2\times 10^3}=5\mathrm{mA}$ Current through $R,I=\frac{V_i-V_Z}{R}$ $=\frac{60-10}{4\times 10^3}=\frac{50}{4\times 10^3}=12.5\mathrm{mA}$ Fom circuit diagram, $$\begin{array}{rl}& I=I_Z+I_L\\ \Rightarrow & 12.5=I_Z+5\\ \Rightarrow & I_7=12.5-5=7.5\mathrm{mA}\end{array}$$