Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionHard2 minPYQ_2014

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A Zener diode, having breakdown voltage equal to $15 V$ is used in a voltage regulator circuit shown in figure. The current through the diode is

Answer:

Solution:

For $R = 1 k Ω$ $i_{1} = \frac{15}{1} mA = 15 mA R = 250Ω i_{250} = \frac{20 - 15}{250} = \frac{5}{250} = 20 mA i_{Zener} = 20 - 15 = 5 mA$

Stream:VITEEESubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2014

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