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Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionMedium2 minPYQ_2011

PhysicsMediumsingle choice

A zener diode, having breakdown voltage equal to $15 V$ , is used in a voltage regulator circuit shown in figure. The current through the diode is
NEET 2011 (Mains)

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Answer:

Solution:

For I $1 k Ω$ $i_{1} = \frac{15}{1} = 15 mA$ For II $250Ω$ $i_{250Ω} = \frac{20 - 15}{250} = \frac{5}{250} = \frac{20}{1000} = 20 mA ∴ i_{zener} = 20 - 15 = 5 mA$

Stream:NEETSubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2011

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