Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsMedium2 minQB

PhysicsMediuminteger

A solid sphere rolling on a rough horizontal surface with a linear speed $7 m / s$ collides elastically with a fixed, smooth, vertical wall. Find the speed of the sphere (in $m / s$ ) after it has started pure rolling in backward direction.

Answer:

Solution:

Applying conservation of angular momentum about point P , we ge

$m v_{0} R - \frac{2}{5} M R^{2} \times \frac{v _{0}}{R} = m v R + \frac{2}{5} m R^{2} \times \frac{v}{R}$

$m v_{0} R (1 - \frac{2}{5}) = m v R (1 + \frac{2}{5}) \Rightarrow v = \frac{3 v _{0}}{7} = \frac{3 \times 7}{7} = 3 m / s$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: QB

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